7.1 Integration By Parts/32

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Revision as of 01:24, 27 November 2022 by Juanr69976@students.laalliance.org (talk | contribs) (Created page with "<math> f'(x)= \int_{0}^{t} e^s sin(t-s) \cdot ds </math> <br><br> <math>\int_{0}^{t} e^s sin(t-s) \cdot ds ~ ~ ~ = ~ ~ ~ e^s \cdot cos(t-s) - \int_{0}^{t} e^s cos(t-s) \cdot ds</math><br> <math> u= e^s ~ ~ ~ ~ ~ dv=sin(t-s)dx ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ u=e^s ~ ~ ~ ~ ~ dv=cos(t-s)</math><br> <math>du= e^s ds~ ~ v=cos(t-s) ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ du=e^s ~ ~ ~ ~ ~ v=-sin(t-s)</math> <br><br> <math>=\frac{32}{5} (\ln(2))^2 -\frac{64}{25} (\ln(2)) + \fr...")
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Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle f'(x)= \int_{0}^{t} e^s sin(t-s) \cdot ds }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{t} e^s sin(t-s) \cdot ds ~ ~ ~ = ~ ~ ~ e^s \cdot cos(t-s) - \int_{0}^{t} e^s cos(t-s) \cdot ds}

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle u=e^{s}~~~~~dv=sin(t-s)dx~~~~~~~~~~~~~~~u=e^{s}~~~~~dv=cos(t-s)}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle du= e^s ds~ ~ v=cos(t-s) ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ du=e^s ~ ~ ~ ~ ~ v=-sin(t-s)}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle =\frac{32}{5} (\ln(2))^2 -\frac{64}{25} (\ln(2)) + \frac{62}{125}}


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