7.1 Integration By Parts/29: Difference between revisions

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<math> f'(x)= \int_{}^{}\cos(x)\ln(sin(x))\cdot dx </math> <br><br>
<math> f'(x)= \int_{}^{}\cos(x)\ln(sin(x))\cdot dx </math> <br><br>


<math>\int_{}^{}\cos(x)\ln(\sin(x))\cdot dx = \int_{}^{}\ln(u)\cdot du ~ ~ ~ = ~ ~ ~ ~ u\ln(u)-\int_{}^{} du =u\ln(u)-u+c</math><br>
<math>\int_{}^{}\cos(x)\ln(\sin(x))\cdot dx ~~~ = ~~~ \int_{}^{}\ln(u)\cdot du ~~~ = ~~~ u\ln(u)-\int_{}^{} du ~~~=~~~ u\ln(u)-u+c</math><br>
<math>u=\sin(x) ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ z=\ln(u) ~ ~ ~ ~ ~ dw=du</math> <br>  
<math>u=\sin(x) \qquad \qquad z=\ln(u) \qquad dw=du</math> <br>  
<math> du=\cos(x)\cdot dx ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ dz=\frac{1}{x}\cdot du ~ ~ w=u</math> <br><br>
<math> du=\cos(x)\cdot dx \qquad dz=\frac{1}{x}\cdot du \qquad w=u</math> <br><br>
<math>\text{Therefore, } f(x)=\sin(x)\ln(\sin(x))-\sin(x)+c</math>
<math>\text{Therefore, } f(x)=\sin(x)\ln(\sin(x))-\sin(x)+c</math>



Latest revision as of 19:07, 28 November 2022








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