7.1 Integration By Parts/29: Difference between revisions
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(Created page with "<math> f'(x)= \int_{}^{}\cos(x)ln(sin(x))\cdot dx </math> <br><br> <math>\int_{}^{}\cos(x)ln(sin(x)\cdot dx=\int_{}^{}\ln(u)\cdot du</math><br> <math>u=sin(x)</math> <br> <math> du=cos(x)dx</math> <br><br> <math>=u \cdot ln(u)-u+c</math><br><br> <math>\text{Therefore, } f(x)=sin(x)ln(sin(x))-sin(x)+c</math>") |
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<math> f'(x)= \int_{}^{}\cos(x)ln(sin(x))\cdot dx </math> <br><br> | <math> f'(x)= \int_{}^{}\cos(x)\ln(sin(x))\cdot dx </math> <br><br> | ||
<math>\int_{}^{}\cos(x)ln(sin(x)\cdot dx=\int_{}^{}\ln(u)\cdot du</math><br> | |||
<math>u=sin(x)</math> <br> <math> du=cos(x)dx | <math>\int_{}^{}\cos(x)\ln(\sin(x))\cdot dx ~~~ = ~~~ \int_{}^{}\ln(u)\cdot du ~~~ = ~~~ u\ln(u)-\int_{}^{} du ~~~=~~~ u\ln(u)-u+c</math><br> | ||
<math>u=\sin(x) \qquad \qquad z=\ln(u) \qquad dw=du</math> <br> | |||
<math>\text{Therefore, } f(x)=sin(x)ln(sin(x))-sin(x)+c</math> | <math> du=\cos(x)\cdot dx \qquad dz=\frac{1}{x}\cdot du \qquad w=u</math> <br><br> | ||
<math>\text{Therefore, } f(x)=\sin(x)\ln(\sin(x))-\sin(x)+c</math> | |||
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