7.1 Integration By Parts/14: Difference between revisions

Latest revision as of 00:18, 2 December 2022

$\int s2^{s}ds=s*{\frac {2^{s}}{ln(2)}}-\int {\frac {2^{s}}{ln(2)}}ds=s*{\frac {2^{s}}{ln(2)}}-{\frac {1}{ln(2)}}*\int 2^{s}ds=s*{\frac {2^{s}}{ln(2)}}-{\frac {1}{ln(2)}}={\frac {s*2^{s}}{ln(2)}}-{\frac {2^{s}}{ln(2)^{2}}}+c$

Revision as of 00:18, 2 December 2022 (view source) Kimberlyl58444@students.laalliance.org (talk \| contribs) (Created page with "<math>\int s2^s ds= s\frac{2^s}{ln(2)}-\int\frac{2^s}{ln(2)}ds= s\frac{2^s}{ln(2)}-\frac{1}{ln(2)}\int 2^s ds=s\frac{2^s}{ln(2)}-\frac{1}{ln(2)}=\frac{s*2^s}{ln(2)}-\frac{2^s}{ln(2)^2}</math>")		Latest revision as of 00:18, 2 December 2022 (view source) Kimberlyl58444@students.laalliance.org (talk \| contribs) No edit summary
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	<math>\int s2^s ds= s\frac{2^s}{ln(2)}-\int\frac{2^s}{ln(2)}ds= s\frac{2^s}{ln(2)}-\frac{1}{ln(2)}\int 2^s ds=s\frac{2^s}{ln(2)}-\frac{1}{ln(2)}=\frac{s*2^s}{ln(2)}-\frac{2^s}{ln(2)^2}</math>		<math>\int s2^s ds= s\frac{2^s}{ln(2)}-\int\frac{2^s}{ln(2)}ds= s\frac{2^s}{ln(2)}-\frac{1}{ln(2)}\int 2^s ds=s\frac{2^s}{ln(2)}-\frac{1}{ln(2)}=\frac{s*2^s}{ln(2)}-\frac{2^s}{ln(2)^2}+c </math>

7.1 Integration By Parts/14: Difference between revisions

Latest revision as of 00:18, 2 December 2022

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