User contributions for Josuem95981@students.laalliance.org

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29 November 2022

  • 05:5605:56, 29 November 2022 diff hist +928 N 7.1 Integration By Parts/22Created page with "<math> \begin{align} &\int_4^9 \frac{\ln(y)}{y}dy \ \ \ \ \ \ u= \ln(y), du=\frac{1}{y}dy \ \ \ \ dv=\frac{1}{\sqrt y}dy, v=2\sqrt y \\[2ex] \\ & u\cdot v \ - \int v du \ = \ \big(\ln(y) \big) \cdot \big( 2\sqrt y \big) - \int \big(2\sqrt y \ \cdot \frac{1}{y} \big)dy \\[2ex] &= 2\sqrt y \ln(y) - \int\frac{2}{\sqrt y }dy \ = \ 2\sqrt y \ln(y) - 2\int \frac{1}{\sqrt y}dy \ = \ 2\sqrt y \ln(y) - 2\int \frac{1}{\sqrt y} \\[2ex] &=2\sqrt y \ln(y)-2 \cdot 2\sqrt y \ = \..." current

25 November 2022

20 September 2022

19 September 2022

18 September 2022

  • 23:5923:59, 18 September 2022 diff hist +35 6.1 Areas Between Curves/17No edit summary
  • 23:5623:56, 18 September 2022 diff hist +998 N 6.1 Areas Between Curves/17Created page with "<math> \begin{align} y = \sqrt{x},\ y=\frac{1}{2}x,\ x=9 \\ \sqrt{x}=\frac{1}{2}x\ \rightarrow \ \sqrt{x}-\frac{1}{2}x=0\ \rightarrow \ \sqrt{4}\ -\frac{1}{2}(4) = 2-2=0,\ x=4 \\ A= \int_{0}^{4} \left[\sqrt{x} - \frac{1}{2}x \right]\mathrm{d}x + \int_{4}^{9} \left[ \frac{1}{2}x - \sqrt{x} \right]\mathrm{d}x \\ = \ \left[\frac{2}{3}x^\frac{3}{2} - \frac{1}{4}x^2 \right]_{0}^{4} \ + \ \left[ \frac{1}{4}x^2 - \frac{2}{3}x^\frac{3}{2} \right]_{4}^{9} \\ =\left[ \fra..."

3 September 2022

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