Je m'appelle Christopher Sanchez. f ( x ) = 2 x − 3 {\displaystyle f(x)=2x-3} g ( x ) = x + 2 {\displaystyle g(x)=x+2} ( f ( g ) ) , ( f − g ) , ( f + g ) , ( f x ) {\displaystyle (f(g)),(f-g),(f+g),({\frac {f}{x}})}
d d x [ c ] = 0 {\displaystyle {\frac {d}{dx}}[c]=0} d d x [ c ⋅ f ( x ) ] = c ⋅ d d x [ f ( x ) ] {\displaystyle {\frac {d}{dx}}[c\cdot f(x)]=c\cdot {\frac {d}{dx}}[f(x)]}
d d x [ f ( x ) ± g ( x ) ] = d d x [ f ( x ) ] ± d d x [ g ( x ) ] {\displaystyle {\frac {d}{dx}}[f(x)\pm g(x)]={\frac {d}{dx}}[f(x)]\pm {\frac {d}{dx}}[g(x)]}
d d x [ / f r a c f g ] = F ′ ( x ) ⋅ g ( x ) − g ′ ( x ) ⋅ f g 2 {\displaystyle {\frac {d}{dx}}[/frac{{\frac {f}{g}}]=F'(x)\cdot g(x)-g'(x)\cdot f}{g^{2}}} d d x [ c ] = 0 {\displaystyle {\frac {d}{dx}}[c]=0}
![{\displaystyle {\frac {d}{dx}}[c]=0}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/834381b512bc1d1fc47c2d26ce38ae71daaa1053)
![{\displaystyle {\frac {d}{dx}}[c\cdot f(x)]=c\cdot {\frac {d}{dx}}[f(x)]}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/e100ac3ba73695d9c36ad8ada81efba4c2a01129)
![{\displaystyle {\frac {d}{dx}}[f(x)\pm g(x)]={\frac {d}{dx}}[f(x)]\pm {\frac {d}{dx}}[g(x)]}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/27fc302c62ab11c846d1255170f40351d3461dfe)
![{\displaystyle {\frac {d}{dx}}[/frac{{\frac {f}{g}}]=F'(x)\cdot g(x)-g'(x)\cdot f}{g^{2}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/e5ec7e6acac06480e5c71d7cdfb872ffe6205beb)