7.1 Integration By Parts/13

From Mr. V Wiki Math
< 7.1 Integration By Parts
Revision as of 21:48, 16 December 2022 by Luiso56189@students.laalliance.org (talk | contribs)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to navigation Jump to search

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int t\sec^2\left(2t\right) dt }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle u = t \qquad dv = \sec^2\left(2t\right) }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle du = dt \qquad v = \frac{1}{2}\tan\left(2t\right)}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int t\sec^2\left(2t\right) dt = \frac{1}{2}\tan\left(2t\right)-\frac{1}{2}\int\tan\left(2t\right)dt = \frac{1}{2}\tan\left(2t\right)-\frac{1}{4}\int\tan\left(u\right)du = \frac{1}{2}\tan\left(2t\right)-\frac{1}{4}\ln|\sec2t|+c }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & u=2t \\[2ex] & du=2dt \\[2ex] & \frac{du}{2}=dt \\[2ex] \end{align} }