∫ x cos 5 x d x u = x d v = cos 5 x d x d u = d x v = 1 5 sin 5 x {\displaystyle {\begin{aligned}\int \,x\cos 5xdx\\[2ex]u=x\qquad dv=\cos 5xdx\\[2ex]du=dx\qquad v={\frac {1}{5}}\sin 5x\end{aligned}}}
![{\displaystyle {\begin{aligned}\int \,x\cos 5xdx\\[2ex]u=x\qquad dv=\cos 5xdx\\[2ex]du=dx\qquad v={\frac {1}{5}}\sin 5x\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/ff0072558f4d2ddd36311f8866d4e7d8d2417bad)