y 2 = x , x = 2 y {\displaystyle y^{2}=x,x=2y}
∫ 0 4 π [ 2 y − y 2 ] d x = π [ 2 ( 4 ) − ( 4 ) ] 2 = {\displaystyle {\begin{aligned}\int _{0}^{4}\pi [2y-y^{2}]dx&=\pi [2(4)-(4)]^{2}\\[2ex]&=\end{aligned}}}
= 64 p i 15 {\displaystyle ={\frac {64pi}{15}}}