7.1 Integration By Parts/25

Failed to parse (syntax error): {\displaystyle \int_{0}^{1}\frac{y}{e^{2y}}dy u=y, -du=dy, dv=\frac{dy}{e^{2}y} &=e^{-2y}dy, v=\frac{-1}{2}e^{-2y} }

${\begin{aligned}\int _{0}^{1}{\frac {y}{e^{2y}}}dy&=\left[{\frac {-1}{2}}ye^{-2y}\right]{\bigg |}_{0}^{1}+{\frac {1}{2}}\int _{0}{1}e^{-2y}dy\\[2ex]&=\left({\frac {-1}{2}}e^{-2}+0\right)-{\frac {1}{4}}\left[e^{-2y}\right]{\bigg |}_{0}^{(}1)\\[2ex]&={\frac {-1}{2}}e^{-2}-{\frac {1}{4}}e^{-2}+{\frac {1}{4}}\\[2ex]&={\frac {1}{4}}-{\frac {3}{4}}e^{-2}\\[2ex]\end{aligned}}$