y = x e − 0.4 x x = 0 , x = 1 {\displaystyle y=xe^{-0.4x}~~~x=0,x=1}
∫ 0 5 x e − 0.4 x d x − 3 ∫ ln ( x ) 2 d x ⏟ {\displaystyle \int _{0}^{5}xe^{-0.4x}dx-\underbrace {3\int \ln(x)^{2}dx} }
