7.1 Integration By Parts/45

${\begin{aligned}&\int _{0}^{\frac {\pi }{2}}sin^{n}(x)dx={\frac {n-1}{n}}\int _{0}^{\frac {\pi }{2}}sin^{n-2}(x)dx\\[2ex]&=-{\frac {1}{n}}cos(x)sin^{n-1}(x)+{\frac {n-1}{n}}{\bigg |}_{0}^{\frac {\pi }{2}}\int _{0}^{\frac {\pi }{2}}sin^{n-2}(x)dx\\[2ex]&=-{\frac {1}{n}}cos({\frac {\pi }{2}})sin^{n-1}({\frac {\pi }{2}})+{\frac {n-1}{n}}\int _{0}^{\frac {\pi }{2}}sin^{n-2}(x)dx\\[2ex]&=-{\frac {1}{n}}(0)(1)+{\frac {n-1}{n}}\int _{0}^{\frac {\pi }{2}}sin^{n-2}(x)dx\\[2ex]&={\frac {n-1}{n}}\int _{0}^{\frac {\pi }{2}}sin^{n-2}(x)dx\\[2ex]\end{aligned}}$

${\begin{aligned}&\int _{0}^{\frac {\pi }{2}}sin^{3}(x)dx\\[2ex]&={\frac {3-1}{3}}\int _{0}^{\frac {\pi }{2}}sin(x)dx\\[2ex]&={\frac {2}{3}}\int _{0}^{\frac {\pi }{2}}sin(x)dx\\[2ex]&={\frac {2}{3}}[-cos(x){\bigg |}_{0}^{\frac {\pi }{2}}\\[2ex]&={\frac {2}{3}}[-cos({\frac {\pi }{2}})-(-cos(0))]\\[2ex]&={\frac {2}{3}}[-1(0)-(-1)]\\[2ex]&={\frac {2}{3}}[1]\\[2ex]&={\frac {2}{3}}\\[2ex]\end{aligned}}$

${\begin{aligned}&\int _{0}^{\frac {\pi }{2}}sin^{5}(x)dx\\[2ex]&={\frac {5-1}{5}}\int _{0}^{\frac {\pi }{2}}sin^{3}(x)dx\\[2ex]&u=cos(x)\\[2ex]&du=-sin(x)\\[2ex]&dx={\frac {du}{-sin(x)}}\\[2ex]&\int sin^{3}(x)dx\\[2ex]&=\int (1-cos^{2}(x))sin(x)dx\\[2ex]&=\int (1-u^{2})sin(x)\cdot {\frac {du}{-sin(x)}}\\[2ex]&=-\int 1-u^{2}du\\[2ex]&={\frac {4}{5}}[-u+{\frac {1}{3}}^{3}(x)]\\[2ex]&={\frac {4}{5}}[-cos(x)+{\frac {1}{3}}cos^{3}(x)]\\[2ex]&={\frac {4}{5}}[-cos({\frac {\pi }{2}})+{\frac {1}{3}}cos^{3}({\frac {\pi }{2}})-(-cos(0)+{\frac {1}{3}}cos^{3}(0))\\[2ex]&={\frac {4}{5}}[(-1)(0)+{\frac {1}{3}}(0)^{3}-((-1)(1)+{\frac {1}{3}}cos^{3}(1)\\[2ex]&={\frac {4}{5}}[-(-1+{\frac {1}{3}}(1)]&={\frac {4}{5}}[{\frac {2}{3}}]&={\frac {8}{15}}\end{aligned}}$