V = ∫ 0 1 π ( x 3 ) 2 = ∫ 0 1 ( π x 6 ) d x {\displaystyle V=\int _{0}^{1}\pi (x^{3})^{2}=\int _{0}^{1}(\pi x^{6})dx} < br> V = | − 1 2 {\displaystyle V=|_{-1}^{2}}
