7.1 Integration By Parts/13

$\int t\sec ^{2}\left(2t\right)dt$

Failed to parse (syntax error): {\displaystyle u = t \qquad dv = \sec^2\left(2t\right) \qquad & = \int\sec^2\left(2t\right)dt \\[2ex] &= \frac{1}{2}\int\sec^2\left(u\right)du \\[2ex] }

$du=dt\qquad v={\frac {1}{2}}\tan \left(2t\right)$