∫ t sec 2 ( 2 t ) d t {\displaystyle \int t\sec ^{2}\left(2t\right)dt}
u = t d v = sec 2 ( 2 t ) ∫ sec 2 ( 2 t ) {\displaystyle u=t\qquad dv=\sec ^{2}\left(2t\right)\qquad \int \sec ^{2}\left(2t\right)} d u = d t v = 1 2 tan ( 2 t ) {\displaystyle du=dt\qquad v={\frac {1}{2}}\tan \left(2t\right)}
