y = 5 ln ( x ) , y = x ln ( x ) {\displaystyle y=5\ln(x),y=x\ln(x)}
5 ln ( x ) = x ln ( x ) x = 5 x = 1 5 ln ( 2 ) > 2 ln ( 2 ) {\displaystyle {\begin{aligned}5\ln(x)&=x\ln(x)\\[1ex]&x=5\\[1ex]&x=1\\[1ex]5\ln(2)>2\ln(2)\end{aligned}}}
∫ 1 5 ( 5 ln ( x ) − x ln ( x ) ) d x = ∫ 1 5 ( 5 ln ( x ) ) d x − ∫ 1 5 ( x ln ( x ) ) d x {\displaystyle \int _{1}^{5}\left(5\ln(x)-x\ln(x)\right)dx=\int _{1}^{5}\left(5\ln(x)\right)dx-\int _{1}^{5}\left(x\ln(x)\right)dx}
![{\displaystyle {\begin{aligned}5\ln(x)&=x\ln(x)\\[1ex]&x=5\\[1ex]&x=1\\[1ex]5\ln(2)>2\ln(2)\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/cd1c3a218d1938f4fbde2e7b79218d92891c3f99)
