f ′ ( x ) = ∫ sin − 1 ( x ) ⋅ d x {\displaystyle f'(x)=\int _{}^{}\sin ^{-1}(x)\cdot dx} ∫ sin − 1 ( x ) d x {\displaystyle \int _{}^{}\sin ^{-1}(x)dx} = x sin − 1 ( x ) − ∫ x 1 − x 2 d x {\displaystyle x\sin ^{-1}(x)-\int _{}^{}{\frac {x}{\sqrt {1-x^{2}}}}dx} = x sin − 1 ( x ) + 1 2 ∫ 1 u d u {\displaystyle x\sin ^{-1}(x)+{\frac {1}{2}}\int _{}^{}{\frac {1}{\sqrt {u}}}du} = x sin − 1 ( x ) + 1 2 ∫ u − 1 2 d u {\displaystyle x\sin ^{-1}(x)+{\frac {1}{2}}\int _{}^{}u^{-{\frac {1}{2}}}du} = x sin − 1 ( x ) + 1 2 ( 2 u f r a c 1 2 {\displaystyle x\sin ^{-1}(x)+{\frac {1}{2}}(2u^{frac{1}{2}}} = x sin − 1 ( x ) + u {\displaystyle x\sin ^{-1}(x)+{\sqrt {u}}} = x sin − 1 ( x ) + 1 − x 2 {\displaystyle x\sin ^{-1}(x)+{\sqrt {1-x^{2}}}}
