7.1 Integration By Parts/29

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Revision as of 20:21, 18 November 2022 by Juanr69976@students.laalliance.org (talk | contribs) (Created page with "<math> f'(x)= \int_{}^{}\cos(x)ln(sin(x))\cdot dx </math> <br><br> <math>\int_{}^{}\cos(x)ln(sin(x)\cdot dx=\int_{}^{}\ln(u)\cdot du</math><br> <math>u=sin(x)</math> <br> <math> du=cos(x)dx</math> <br><br> <math>=u \cdot ln(u)-u+c</math><br><br> <math>\text{Therefore, } f(x)=sin(x)ln(sin(x))-sin(x)+c</math>")
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Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle f'(x)= \int_{}^{}\cos(x)ln(sin(x))\cdot dx }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{}\cos(x)ln(sin(x)\cdot dx=\int_{}^{}\ln(u)\cdot du}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle u=sin(x)}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle du=cos(x)dx}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle =u \cdot ln(u)-u+c}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \text{Therefore, } f(x)=sin(x)ln(sin(x))-sin(x)+c}

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