5.4 Indefinite Integrals and the Net Change Theorem/41
< 5.4 Indefinite Integrals and the Net Change Theorem
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Revision as of 16:33, 21 September 2022 by Dvaezazizi@laalliance.org (talk | contribs)
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int _{0}^{\frac {1}{\sqrt {3}}}{\frac {t^{2}-1}{t^{4}-1}}dt&=\int _{0}^{\frac {1}{\sqrt {3}}}{\frac {(t^{2}-1)}{(t^{2}-1)(t^{2}+1)}}dt=\int _{0}^{\frac {1}{\sqrt {3}}}{\frac {1}{(t^{2}+1)}}dt\\[2ex]&=\arctan {(t)}{\bigg |}_{0}^{\frac {1}{\sqrt {3}}}\\[2ex]&=\left[\arctan \left({\frac {1}{\sqrt {3}}}\right)\right]-[\arctan(0)]\\[2ex]&={\frac {\pi }{6}}-0\\[2ex]&={\frac {\pi }{6}}\end{aligned}}}