5.5 The Substitution Rule/69
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Revision as of 15:47, 6 September 2022 by Naydelinr58421@students.laalliance.org (talk | contribs)
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{0}^{1} \left(\frac{e^z + 1}{e^z + z}\right) &= \int_{}^{} \left((e^z +1) (\frac{1}{e^z +z}) \right) u= e^z + z du= e^z +1 \end{align} }