5.3 The Fundamental Theorem of Calculus/33

$h(x)=\int _{2}^{1/x}\arctan(t)dt$

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {d}{dx}}\left[h(x)\right]={\frac {d}{dx}}\left[int_{2}^{1/x}\arctan(t)dt\right]{\frac {-1}{x^{2}}}\left(\arctan({\frac {1}{x}}\right)-0}