Hallo mein heiße ist Jeremy f ( x ) = 4 x 3 + 9 y 4 3 x 3 {\displaystyle f(x)={\sqrt[{3}]{\frac {4x^{3}+9y_{4}^{3}}{x}}}} g ( x ) = 3 x 9 − 7 − 5 {\displaystyle g(x)={\sqrt[{-5}]{3x^{9}-7}}} ( f + g ) ( x ) = 4 x 3 + 9 y 4 3 x 3 + 3 x 9 − 7 − 5 {\displaystyle (f+g)(x)={\sqrt[{3}]{\frac {4x^{3}+9y_{4}^{3}}{x}}}+{\sqrt[{-5}]{3x^{9}-7}}}
d d x ( f ( x ) g ( x ) ) = f ′ ( x ) ⋅ g ( x ) − g ′ ( x ) f ( x ) ( g ( x ) ) 2 E x : {\displaystyle {\frac {d}{dx}}({\frac {f(x)}{g(x)}})={\frac {f'(x)\cdot g(x)-g'(x)f(x)}{(g(x))^{2}}}Ex:}