Chris

Je m'appelle Christopher Sanchez.
$f(x)=2x-3$
$g(x)=x+2$
$(f(g)),(f-g),(f+g),({\frac {f}{x}})$

Review

${\frac {d}{dx}}[c]=0$
${\frac {d}{dx}}[c\cdot f(x)]=c\cdot {\frac {d}{dx}}[f(x)]$

${\frac {d}{dx}}[f(x)\pm g(x)]={\frac {d}{dx}}[f(x)]\pm {\frac {d}{dx}}[g(x)]$

Quotient Rule

Failed to parse (syntax error): {\displaystyle {\frac{d}{dx}} [\frac{f}{g}}] = F'(x) \cdot g(x) - g'(x) \cdot f g^2 }
${\frac {d}{dx}}[c]=0$