∫ sin 2 ( x ) d x = − 1 2 cos ( x ) ⋅ sin 2 − 1 x + 2 − 1 2 ∫ sin 0 ( x ) d x {\displaystyle \int \sin ^{2}(x)dx=-{\frac {1}{2}}\cos(x)\cdot \sin ^{2-1}x+{\frac {2-1}{2}}\int \sin ^{0}(x)dx}
