5.3 The Fundamental Theorem of Calculus/17

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle y=\int_{1-3x}^{1}\frac{u^3}{1+u^2} du}

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {d}{dx}}(y)={\frac {d}{dx}}\left(\int _{1-3x}^{1}{\frac {u^{3}}{(1+u^{2})}}du\right)=(0)\cdot {\frac {(1)^{3}}{(1+(1)^{2})}}-(-3)\cdot {\frac {(1-3x)^{3}}{(1+(1-3x)^{2})}}}

${\text{Therefore, }}y'={\frac {3(1-3x)^{3}}{1+(1-3x)^{2}}}$