7.1 Integration By Parts/28: Difference between revisions
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<math> | <math> | ||
\begin{align} | \begin{align} | ||
\int_{1}^{2}\frac{\ln{x}^2}{x^3} & = -\frac{\ln^2{(x)}}{2x^2} - \int-\frac{\ln{ | \int_{1}^{2}\frac{\ln{x}^2}{x^3} & = -\frac{\ln^2{(x)}}{2x^2} - \int-\frac{\ln{x}{x^3} \\[2ex] | ||
& = -\frac{\ln{(x)}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] | & = -\frac{\ln{(x)}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] |
Revision as of 22:11, 16 December 2022
Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} \int_{1}^{2}\frac{\ln{x}^2}{x^3} & = -\frac{\ln^2{(x)}}{2x^2} - \int-\frac{\ln{x}{x^3} \\[2ex] & = -\frac{\ln{(x)}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] & = -\frac{\ln{(x)}}{2x^2} - \frac{1}{4x^2} \end{align} }