7.1 Integration By Parts/28: Difference between revisions

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<math>
<math>
\begin{align}
\begin{align}
\int_{1}^{2}\frac{\ln{x}^2}{x^3} & = -\frac{\ln^2{(x)}}{2x^2} - \int-\frac{1}{2x^3} \\[2ex]
\int_{1}^{2}\frac{\ln{x}^2}{x^3} & = -\frac{\ln^2{(x)}}{2x^2} - \int-\frac{\ln{(x)}{x^3} \\[2ex]


& = -\frac{\ln{(x)}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex]
& = -\frac{\ln{(x)}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex]

Revision as of 22:11, 16 December 2022



Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} \int_{1}^{2}\frac{\ln{x}^2}{x^3} & = -\frac{\ln^2{(x)}}{2x^2} - \int-\frac{\ln{(x)}{x^3} \\[2ex] & = -\frac{\ln{(x)}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] & = -\frac{\ln{(x)}}{2x^2} - \frac{1}{4x^2} \end{align} }