7.1 Integration By Parts/28: Difference between revisions
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<math> | <math> | ||
\begin{align} | \begin{align} | ||
\int_{1}^{2}\frac{\ln{x}^2}{x^3} = -\frac{\ln{x}}{2x^2} - \int-\frac{1}{2x^3} | & \int_{1}^{2}\frac{\ln{x}^2}{x^3} = -\frac{\ln{x}}{2x^2} - \int-\frac{1}{2x^3} \\[2ex] | ||
& = -\frac{\ln{x}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] | & = -\frac{\ln{x}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] | ||
Revision as of 21:58, 16 December 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int _{1}^{2}{\frac {\ln {x}^{2}}{x^{3}}}=-{\frac {\ln {x}}{2x^{2}}}-\int -{\frac {1}{2x^{3}}}\\[2ex]&=-{\frac {\ln {x}}{2x^{2}}}-{\frac {1}{2}}\int {\frac {1}{x^{3}}}\\[2ex]\end{aligned}}}