6.5 Average Value of a Function/5: Difference between revisions
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<math> | <math> | ||
f(t) = te^{-t^2} | f(t) = te^{-t^2} \quad [0, 5] \\ | ||
\begin{align} | |||
f_{avg} = \frac{1}{5}\int_{0}^{5}te^{-t^2}\,dx | |||
\end{align} | |||
</math> | </math> | ||
Revision as of 18:41, 16 December 2022
Failed to parse (syntax error): {\displaystyle f(t) = te^{-t^2} \quad [0, 5] \\ \begin{align} f_{avg} = \frac{1}{5}\int_{0}^{5}te^{-t^2}\,dx \end{align} }