6.2 Volumes/9: Difference between revisions

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\int_{0}^{4}\pi [2y-y^2]dx &= \pi[2(4)-(4)^{2}] \\[2ex]
\int_{0}^{4}\pi [2y-y^2]dx &= \pi[2(4)-(4)^{2}] \\[2ex]
&= \pi[8-16] \\[2ex]
&= \pi[8-16] \\[2ex]
&= \frac{64pi}{15}
\end{align}
\end{align}
</math>
</math>
<math>=\frac{64pi}{15}</math>

Revision as of 02:11, 16 December 2022