7.1 Integration By Parts/53

$y=xe^{-0.4x}~~~x=0,x=1$

${\begin{aligned}\underbrace {\int _{0}^{5}xe^{-0.4x}dx} _{\begin{aligned}u&=x&dv&=e^{-0.4x}dx\\[0.6ex]du&=dx&v&={\frac {5}{2}}e^{-0.4x}\end{aligned}}\\[2ex]\end{aligned}}$

$\left[{\frac {5}{2}}e^{-0.4x}\right]+\int _{5}^{0}{\frac {5}{2}}e^{-0.4x}dx$

${\begin{aligned}u&=-0.4x\\[2ex]du&=dx\\[2ex]\end{aligned}}$

$\left(-{\frac {25}{2}}e^{-2}-0\right)+{\frac {5}{4}}\int _{5}^{0}e^{u}$

<math> -\frac{25}{2}e^{-2}+\left [ \frac{5}{4}\left ( e^{-0.4x} \right ) \right ] Rubyp61202@students.laalliance.org (talk)=Rubyp61202@students.laalliance.org (talk)