7.1 Integration By Parts/53: Difference between revisions

Revision as of 12:28, 13 December 2022

$y=xe^{-0.4x}~~~x=0,x=1$

$\int _{0}^{5}xe^{-0.4x}dx-\underbrace {3\int \ln(x)^{2}dx}$

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	<math>y= xe^{-0.4x} ~~~ x=0,x=1</math>		<math>y= xe^{-0.4x} ~~~ x=0,x=1</math>

	<math>\int_{0}^{5}xe^{-0.4x}dx -\underbrace{3\int\ln(x)^2dx}_{ </math>		<math>\int_{0}^{5}xe^{-0.4x}dx -\underbrace{3\int\ln(x)^2dx} </math>