7.1 Integration By Parts/51b: Difference between revisions

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du & = \tfrac{2\ln{(x)}}{x}dx  & v &= x
du & = \tfrac{2\ln{(x)}}{x}dx  & v &= x
\end{aligned}
\end{aligned}
} \\ [1ex]
} \\ [2ex]


&= x\ln^{3}(x) -3\left[\ln^{2}{(x)}\cdot x - 2\int\ln{(x)}dx\right] \\ [1ex]
&= x\ln^{3}(x) -3\left[\ln^{2}{(x)}\cdot x - 2\int\ln{(x)}dx\right] \\ [1ex]
Line 18: Line 18:
u & = \ln{(x)}  & dv &= dx \\[0.6ex]
u & = \ln{(x)}  & dv &= dx \\[0.6ex]
du & = \tfrac{1}{x}dx  & v &= x
du & = \tfrac{1}{x}dx  & v &= x
\end{aligned}} \\ [1ex]
\end{aligned}} \\ [2ex]


&= x\ln^{3}(x) -3x\ln^{2}{(x)} + 6\left[\ln{(x)}\cdot x - \int dx\right] \\[1ex]
&= x\ln^{3}(x) -3x\ln^{2}{(x)} + 6\left[\ln{(x)}\cdot x - \int dx\right] \\[1ex]

Revision as of 18:14, 29 November 2022