7.1 Integration By Parts/49: Difference between revisions
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<math> | <math> | ||
\int_{}^{} \left(\tan^{n}(x)\right)dx = \int_{}^{} \left((\tan^{2}x)(\tan^{n-2}x)\right)dx = \int_{}^{} (\sec^{2}(x)-1)\tan^{n-2}x dx | \int_{}^{} \left(\tan^{n}(x)\right)dx = \int_{}^{} \left((\tan^{2}x)(\tan^{n-2}x)\right)dx = \int_{}^{} (\sec^{2}(x)-1)\tan^{n-2}x dx | ||
&= \int_{}^{} (\sec^{2}x)(\tan^{n-2}x) | &= \int_{}^{} (\sec^{2}x)(\tan^{n-2}x)dx | ||
</math> | </math> | ||
Revision as of 18:07, 29 November 2022
Prove Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} \left(\tan^{n}(x)\right)dx =\frac{\tan^{n-1}x}{n-1} - \int_{}^{} \left(\tan^{n-2}x\right)dx }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} \left(\tan^{n}(x)\right)dx = \int_{}^{} \left((\tan^{2}x)(\tan^{n-2}x)\right)dx = \int_{}^{} (\sec^{2}(x)-1)\tan^{n-2}x dx &= \int_{}^{} (\sec^{2}x)(\tan^{n-2}x)dx }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} &u = \tan^{n-2}x \quad dv= 1dx \\[2ex] &du =1dx \quad v=x \\[2ex] \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{}^{} \left(\ln(x)^{n}\right)dx &= x \ln(x)^{n} - \int_{}^{} \left((x \frac{n \ln(x)^{n-1}}{x}) \right)dx \\[2ex] &= x \ln(x)^{n} - \int_{}^{} \left(n \ln(x)^{n-1} \right)dx \\[2ex] &= x \ln(x)^{n} - n \int_{}^{} \left(\ln(x)^{n-1} \right)dx \\[2ex] \end{align} }