7.1 Integration By Parts/51b: Difference between revisions

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du & = \tfrac{2\ln{(x)}}{x}dx  & v &= x
du & = \tfrac{2\ln{(x)}}{x}dx  & v &= x
\end{aligned}
\end{aligned}
} \\ [0.8ex]
} \\ [1ex]


&= x\ln(x)^3 -3\left[\ln^{2}{(x)}\cdot x - 2\int\ln{(x)}dx\right] \\ [0.8ex]
&= x\ln(x)^3 -3\left[\ln^{2}{(x)}\cdot x - 2\int\ln{(x)}dx\right] \\ [1ex]
\end{align}
\end{align}


</math>
</math>

Revision as of 17:55, 29 November 2022





Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int \ln(x)^{3}dx&=x\ln(x)^{3}-\underbrace {3\int \ln(x)^{2}dx} _{\begin{aligned}u&=\ln ^{2}{(x)}&dv&=dx\\[0.6ex]du&={\tfrac {2\ln {(x)}}{x}}dx&v&=x\end{aligned}}\\[1ex]&=x\ln(x)^{3}-3\left[\ln ^{2}{(x)}\cdot x-2\int \ln {(x)}dx\right]\\[1ex]\end{aligned}}}