7.1 Integration By Parts/30: Difference between revisions

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<math> \int_{0}^{1}\frac{r^{3}}{\sqrt{4+r^{2}}}\cdot dr  ~~~ = ~~~  \int_{0}^{1}r^{3}\cdot \frac{1}{\sqrt{4+r^{2}}}\cdot dr  </math>
<math> \int_{0}^{1}\frac{r^{3}}{\sqrt{4+r^{2}}}\cdot dr  ~~~ = ~~~  \int_{0}^{1}r^{3}\cdot \frac{1}{\sqrt{4+r^{2}}}\cdot dr  </math>
<math>
\begin{align}
u &= \arcsin {x}
  \\[2ex]
du &= \frac{1}{\sqrt{1-x^2}}\;dx \\[2ex]
\end{align}
</math>

Revision as of 11:46, 29 November 2022