7.1 Integration By Parts/13: Difference between revisions

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<math>\int t\sec^2\left(2t\right) dt </math>
<math>\int t\sec^2\left(2t\right) dt </math>


<math>u = t \qquad dv = \sec^2\left(2t\right) \qquad \int\sec^2\left(2t\right)</math> <br><br>
<math>u = t \qquad dv = \sec^2\left(2t\right) \qquad \int\sec^2\left(2t\right)dt</math> <br><br>
<math>du = dt \qquad v = \frac{1}{2}\tan\left(2t\right)</math>
<math>du = dt \qquad v = \frac{1}{2}\tan\left(2t\right)</math>

Revision as of 02:58, 29 November 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int t\sec^2\left(2t\right) dt }

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle u=t\qquad dv=\sec ^{2}\left(2t\right)\qquad \int \sec ^{2}\left(2t\right)dt}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle du = dt \qquad v = \frac{1}{2}\tan\left(2t\right)}