7.1 Integration By Parts/43: Difference between revisions

Revision as of 21:21, 28 November 2022

 $\int \sin ^{2}(x)dx=-{\frac {1}{2}}\cos(x)\cdot \sin ^{2-1}x+{\frac {2-1}{2}}\int \sin ^{0}(x)dx$

Revision as of 21:18, 28 November 2022 (view source) Elizabethh58413 (talk \| contribs) (Created page with " <math> \int{sin^2x}dx = - \frac{1}{2}cos(x) \cdot sin^{2-1}x + \frac{2-1}{2} \int sin^0xdx </math> <br><br>")		Revision as of 21:21, 28 November 2022 (view source) Elizabethh58413 (talk \| contribs) No edit summary Newer edit →
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	<math> \int{sin^~~2x}~~dx = - \frac{1}{2}cos(x) \cdot sin^{2-1}x + \frac{2-1}{2} \int sin^~~0xdx~~ </math> <br><br>		<math> \int\sin^2(x)dx = - \frac{1}{2}\cos(x) \cdot \sin^{2-1}x + \frac{2-1}{2} \int\sin^{0}(x)dx </math> <br><br>