7.1 Integration By Parts/33: Difference between revisions

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{u} = <math>\sqrt{x}</math>
<math>{u}</math> = <math>\sqrt{x}</math>


{du} = <math>\frac{1}{2\sqrt{x}}du</math>
<math>{du}</math> = <math>\frac{1}{2\sqrt{x}}du</math>

Revision as of 01:18, 23 November 2022

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