5.4 Indefinite Integrals and the Net Change Theorem/39: Difference between revisions
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<math>\int_{1}^{64}\frac{1+\sqrt[3]{x}}\sqrt{x}dx</math> | <math> | ||
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\int_{1}^{64}\frac{1+\sqrt[3]{x}}\sqrt{x}dx</math> | |||
= \int_{1}^{64}\left(\frac{1}{x^{1/2}} + \frac{x^{1/3}}{x^{1/2}}\right)dx | |||
</math> | |||
= <math>\int_{1}^{64}x^{-1/2}+x^{\frac{1}{3}-{\frac{1}{2}}}</math> = <math>\int_{1}^{64}x^{-\frac{1}{2}}+x^{-\frac{1}{6}}</math> | = <math>\int_{1}^{64}x^{-1/2}+x^{\frac{1}{3}-{\frac{1}{2}}}</math> = <math>\int_{1}^{64}x^{-\frac{1}{2}}+x^{-\frac{1}{6}}</math> | ||
Revision as of 16:11, 21 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}\frac{1+\sqrt[3]{x}}\sqrt{x}dx} = \int_{1}^{64}\left(\frac{1}{x^{1/2}} + \frac{x^{1/3}}{x^{1/2}}\right)dx
</math>
= =
Add one to the exponents and divide by the new exponent
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= =
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= = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle 51.2}
= Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{256}{5}}