6.1 Areas Between Curves/10: Difference between revisions
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<math> | <math> | ||
\begin{align} | \begin{align} | ||
1+\sqrt{x} = \frac{3+x}{3} \\ | &= 1+\sqrt{x} = \frac{3+x}{3} \\ | ||
&= 1+\sqrt{x}-\frac{3+x}{3} = 0 \\ | &= 1+\sqrt{x}-\frac{3+x}{3} = 0 \\ | ||
&= \frac{3+3\sqrt{x}}{3}-\frac{3+x}{3} = 0 \\ | &= \frac{3+3\sqrt{x}}{3}-\frac{3+x}{3} = 0 \\ | ||
Revision as of 04:39, 20 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \color{red}\mathbf{y=1+\sqrt{x}} & \color{royalblue}\mathbf{y=\frac{3+x}{3}} \\ \\ \end{align} }
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&=1+{\sqrt {x}}={\frac {3+x}{3}}\\&=1+{\sqrt {x}}-{\frac {3+x}{3}}=0\\&={\frac {3+3{\sqrt {x}}}{3}}-{\frac {3+x}{3}}=0\\&=3+3{\sqrt {x}}-3+x=0\\&=3{\sqrt {x}}+x=0\\&=3{\sqrt {x}}=-x\\&=9x=x^{2}\\&=9x-x^{2}=0\\&=x(9-x)=0\\&=x=0,9\end{aligned}}}