6.1 Areas Between Curves/23

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \color{red} \mathbf{y=\cos(x)} & \color{royalblue}\mathbf{y=\sin(2x)} \\ & x=0 & x=\frac{\pi}{2}\\ \end{align} }

${\begin{aligned}\cos(x)&=\sin(2x)\\x&={\frac {\pi }{2}}\\x&={\frac {\pi }{6}}\\\end{aligned}}$

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{\frac{\pi}{6}} \left(\cos(x) - \sin(2x) \right)dx + \int_{\frac{\pi}{6}}^{\frac{\pi}{2}} \left(\sin(2x)- \cos(x) \right)dx }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{0}^{\frac{\pi}{6}} \left(\cos(x) - \sin(2x) \right)dx &= \left[\sin(x)+\frac{1}{2}\cos(2x) \right]\Bigg|_{0}^{\frac{\pi}{6}} \\[2ex] &= \left[\sin(\frac{\pi}{6})+\frac{1}{2}\cos(\frac{2\pi}{6})\right]-\left[\sin(0)+\frac{1}{2}\cos(2(0))\right] \\[2ex] &= \left[\frac{1}{2}+\frac{1}{2}\left(\frac{1}{2}\right)\right]-\left[0-\frac{1}{2} (1)\right] \\[2ex] &= \frac{1}{2}+\frac{1}{4}-\left[0+\frac{1}{2}\right] \\ &= \frac{1}{4} \end{align} }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{\frac{\pi}{6}}^{\frac{\pi}{2}} \left[\sin(2x)-\cos(x)\right]dx &= \left[-\frac{1}{2}\cos(2x) - \sin(x) \right]\Bigg|_{\frac{\pi}{6}}^{\frac{\pi}{2}} \\ &= \left[-\frac{1}{2}\cos(\frac{2\pi}{2})-sin(\frac{\pi}{2})\right] - \left[-\frac{1}{2}\cos{\frac{2\pi}{6}} - sin(\frac{\pi}{6})\right] \end{align} }