5.4 Indefinite Integrals and the Net Change Theorem/3: Difference between revisions

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& =\cos{x} - \sin^2{x}\cos{x} \\[2ex]
& =\cos{x} - \sin^2{x}\cos{x} \\[2ex]


& =\cos{x} - (1-cos^2(x))\cos{x} \\[2ex]
& =\cos{x} - (1-cos^2{x})\cos{x} \\[2ex]


& = \cos^3{x}
& = \cos^3{x}

Revision as of 17:15, 13 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int\cos^{3}xdx = \sin{x}-\frac{1}{3}\sin^{3}x+C }


Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}{\frac {d}{dx}}{[\sin {x}-{\frac {1}{3}}\sin ^{3}{x}+C]}&={\cos {x}-{\frac {1}{3}}\cdot 3\sin ^{2}{x}\cos {x}+0}\\[2ex]&=\cos {x}-\sin ^{2}{x}\cos {x}\\[2ex]&=\cos {x}-(1-cos^{2}{x})\cos {x}\\[2ex]&=\cos ^{3}{x}\end{aligned}}}


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