5.3 The Fundamental Theorem of Calculus/23: Difference between revisions

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&=\frac{5\sqrt[5]{(1)^9}}{9}-\frac{5 \sqrt[5]{(0)^9}}{9} \\[2ex]
&=\frac{5\sqrt[5]{(1)^9}}{9}-\frac{5 \sqrt[5]{(0)^9}}{9} \\[2ex]


&=\cfrac{5}{9}
&=\frac{5}{9}


\end{align}
\end{align}
</math>
</math>

Revision as of 22:00, 7 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{0}^{1}x^{\frac{4}{5}}dx &=\frac{x^{\frac{4}{5}+1}}{\frac{4}{5}+1} \Bigg|_{0}^{1} =\frac{x^{\frac{9}{5}}}{\frac{9}{5}} \Bigg|_{0}^{1} \\[2ex] &=\frac{5\sqrt[5]{(1)^9}}{9}-\frac{5 \sqrt[5]{(0)^9}}{9} \\[2ex] &=\frac{5}{9} \end{align} }