5.5 The Substitution Rule/51: Difference between revisions
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\begin{align} | \begin{align} | ||
\int {u^{25}} du = \frac{1}{26}{u^{26}} \\[2ex] | |||
&= \cfrac{(x-1)^{26}} {26}\bigg|_{0}^{2} \\[2ex] | &= \cfrac{(x-1)^{26}} {26}\bigg|_{0}^{2} \\[2ex] | ||
Revision as of 17:25, 7 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int_{0}^{2} ({x-1})^{25} dx \\[2ex] \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= x-1 \\[2ex] du &= dx \\[2ex] \end{align} }
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int {u^{25}}du={\frac {1}{26}}{u^{26}}\\[2ex]&={\cfrac {(x-1)^{26}}{26}}{\bigg |}_{0}^{2}\\[2ex]&={\cfrac {(2-1)^{26}}{26}}-{\cfrac {(0-1)^{26}}{26}}\\[2ex]&=0\end{aligned}}}