5.5 The Substitution Rule/51: Difference between revisions

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\end{align}
\end{align}
</math>
</math>
<math>
\begin{align}


& \int {u^{25}} du &= \frac{1}{26}{u^{26}} \\[2ex]
& \int {u^{25}} du &= \frac{1}{26}{u^{26}} \\[2ex]

Revision as of 17:21, 7 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int_{0}^{2} ({x-1})^{25} dx \\[2ex] \end{align} }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int {u^{25}} du &= \frac{1}{26}{u^{26}} \\[2ex] &= \cfrac{(x-1)^{26}} {26}\bigg|_{0}^{2} \\[2ex] & \cfrac{(2-1)^{26}} {26} - \cfrac {(0-1)^{26}} {26} \\[2ex] &= 0 \end{align} }