5.3 The Fundamental Theorem of Calculus/29: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 1: | Line 1: | ||
<math> | <math> | ||
\int_{1}^{9}\frac{x-1}{\sqrt{x}} dx = | \int_{1}^{9}\frac{x-1}{\sqrt{x}} dx = \int_{1}^{9}\frac{x}{\sqrt{x}}-\frac{1}{\sqrt{x}} = \int_{1}^{9} | ||
</math> | </math> | ||
Revision as of 02:27, 7 September 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{1}^{9}{\frac {x-1}{\sqrt {x}}}dx=\int _{1}^{9}{\frac {x}{\sqrt {x}}}-{\frac {1}{\sqrt {x}}}=\int _{1}^{9}}