5.3 The Fundamental Theorem of Calculus/31: Difference between revisions
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<math> \int_{0}^{\frac{\pi}{4}}\sec^{2}(t)\,dt = \int_{0}^\frac{\pi}{4}sec^{2}(t)dt= tan(\frac{\pi}{4})-tan(0)=1-0=1 | |||
<math> \int_{0}^\frac{\pi}{4}sec^{2}(t)dt | |||
\int_{0}^\frac{\pi}{4}sec^{2}(t)dt= tan(\frac{\pi}{4})-tan(0)=1-0=1 | |||
</math> | </math> | ||
Revision as of 21:22, 6 September 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{0}^{\frac {\pi }{4}}\sec ^{2}(t)\,dt=\int _{0}^{\frac {\pi }{4}}sec^{2}(t)dt=tan({\frac {\pi }{4}})-tan(0)=1-0=1}
Therefore, Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{0}^{\frac {\pi }{4}}sec^{2}(t)dt=1}
(Use FTC #2,) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{a}^{b}f(x)dt = F(b)-F(a) }