5.3 The Fundamental Theorem of Calculus/23: Difference between revisions
Jump to navigation
Jump to search
Osbeenb61996 (talk | contribs) No edit summary |
No edit summary |
||
| Line 3: | Line 3: | ||
&\int_{0}^{1}x^\ | &\int_{0}^{1}x^{\frac{4}{5}}dx \\[2ex] | ||
Revision as of 20:41, 6 September 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int _{0}^{1}x^{\frac {4}{5}}dx\\[2ex]&{\cfrac {5\cdot {\sqrt[{5}]{x^{4}}}}{9}}{\bigg |}_{0}^{1}\\[2ex]&{\cfrac {5\cdot {\sqrt {1^{4}}}}{9}}-{\cfrac {5{\sqrt[{5}]{0^{4}}}}{9}}\\[2ex]&={\cfrac {5}{9}}\end{aligned}}}