5.3 The Fundamental Theorem of Calculus/21: Difference between revisions
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\ | \int_{1}^{4}(5-2t+3t^2)\,dt=5t-t^2+t^3\bigg|_{1}^{4}=5\cdot4-4^2+4^3-(5\cdot1-1^2+1^3)=63 | ||
</math> | </math> | ||
Revision as of 20:38, 6 September 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{1}^{4}(5-2t+3t^{2})\,dt=5t-t^{2}+t^{3}{\bigg |}_{1}^{4}=5\cdot 4-4^{2}+4^{3}-(5\cdot 1-1^{2}+1^{3})=63}